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The maximum amount of current that could flow through the Collector pin is mA, hence we cannot connect loads that consume more than mA using this transistor. To bias a transistor we have to supply current to base pin, this current IB should be limited to 5mA. When this transistor is fully biased then it can allow a maximum of mA to flow across the collector and emitter. When base current is removed the transistor becomes fully off, this stage is called as the Cut-off Region and the Base Emitter voltage could be around mV.
But there are two important features that distinguish both. So if you looking for an NPN transistor that could switch loads of higher current then 2NA might the right choice for your project. How to use 2NA This transistor like all can be used either as a switch or as an amplifier. The Base-Emitter voltage of this transistor is 6V so you just have to supply this voltage across the base and emitter of the transistor to induce a base current into the transistor.
This transistor will make it forward biased and thus closes the connection between collector and emitter. However one important thing to notice is the Base resistor a. As the name suggests this resistor will limit the current flowing through the transistor to prevent it from damaging.
In actual circuit modifications might be required. I have used a base voltage of 5V and a value of 1K as current limiting resistor. Note that the motor here draws about mA from the 12V power source, since the 2N has collector current rating upto mA this circuit is possible had it been a BC the transistor should have been burnt. Can be used to switch high current upto mA loads It can also be used in the various switching applications.
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